Exam 1z0-819 topic 1 question 174 discussion

Actual exam question from Oracle's 1z0-819

Question #: 174
Topic #: 1

[All 1z0-819 Questions]

Given:

Which action will enable the code to compile?

A. Replace line 6 with BiFunction func = x -> y -> x * y;
B. Replace line 6 with Function func = x -> y -> x * y;
C. Replace line 6 with IntFunction func = x -> y -> x * y;
D. Replace line 6 with IntFunction func = x -> y -> x * y;

Show Suggested Answer

Suggested Answer: C 🗳️

by KiraguJohn at July 9, 2023, 7:02 p.m.

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d7bb0b2

1 year ago

NO ANSWER CORRECT THE ONLY wait to this is ok is: IntFunction<IntUnaryOperator> func = x -> y -> x * y; then instream.map(func.apply(...)).....

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ASPushkin

11 months, 3 weeks ago

IntFunction is a raw type and it equals to IntFunction<Object> so right answer is IntFunction<IntUnaryOperator> func = x-> y->x*y;

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d7bb0b2

1 year ago

Instream.map() method only aceppt IntUnaryOperator not IntFunction

upvoted 1 times

ASPushkin

11 months, 3 weeks ago

B) is not right 1) Function is raw type 2) func.apply(10) has just one input parameter

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answer : looks like C and D(same) "func" should have input : int and output: IntUnaryOperator Correct answer : IntFunction<IntUnaryOperator> func = x->y->x*y; IntUnaryOperator oper = y->x*y; where x and y are type of int by definition

upvoted 2 times

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[Removed]

1 year, 4 months ago

There's so much missing in this question it's almost impossible to even try to solve this. ALSO C & D are the exact same.

upvoted 1 times

[Removed]

1 year, 4 months ago

It's definitely not A as the BiFunction's apply method takes 2 parameters. I'm guessing the correct answer has to be something like this IntFunction<IntFunction<Integer>>

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d7bb0b2

1 year ago

IntFunction<IntFunction<Integer>> can not resolve the problem because map of Instream only aceppt IntUnaryOperator not IntFunction

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KiraguJohn

1 year, 6 months ago

What is the difference between C and D?

upvoted 2 times

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