Exam 1z0-809 topic 1 question 32 discussion

answer is D. java.lang.ClassCastException Vehicle cannot be cast to java.lang.Comparable

There is no compilation issues, so you do not need to implement the Comparable interface in order for the code to run You will encounter a runtime exception stating the Vehicle class can not be cast to Comparable

Answer is D if this.vno = vno,; is in correct format

D is correct since Vehicle doesn't implement Comparable.

The answer is C, the reason being that in the line "this.vno = vno,;" the variable has "," at the end, this causes the code not to compile. If the line is corrected to "this.vno = vno;" the answer would be D because java.lang.ClassCastException Vehicle cannot be cast to java.lang.Comparable

Correct answer is D. Missing implementing Comparable interface

Change Vehicle class -->>>> class Vehicle implements Comparable<Vehicle> { int vno; String name; public Vehicle(int vno, String name){ this.vno = vno; this.name = name; } public String toString() { return vno + name; } @Override public int compareTo(Vehicle o) { if (vno > o.vno) return 1; else return 0; } }

D: Exception in thread "main" java.lang.ClassCastException: class test.Vehicle cannot be cast to class java.lang.Comparable (test.Vehicle is in unnamed module of loader 'app'; java.lang.Comparable is in module java.base of loader 'bootstrap')

C is correct in order for the code to run, the class vehicle needs to implement comparable interface, nad override the compareTo method. class Vehicle implements Comparable<Vehicle>{ int vno; String name; public Vehicle (int vno, String name) { this.vno = vno; this.name = name; } public String toString () { return vno + ":" + name; } @Override public int compareTo(Vehicle o) { return this.name.compareTo(o.name); } }

ClassCastException is thrown at run time

The answer is C: ClassCastException