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Exam 1z0-809 topic 1 question 129 discussion

Actual exam question from Oracle's 1z0-809
Question #: 129
Topic #: 1
[All 1z0-809 Questions]

Given the code fragment:

What is the result?

  • A. Java EEJava EESE
  • B. Java EESE
  • C. The program prints either: Java EEJava SE or Java SEJava EE
  • D. Java EEJava SE
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Suggested Answer: D 🗳️
by Abdullah_Rahahleah at Dec. 21, 2020, 12:22 p.m.

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vidhuharu
7 months, 1 week ago
Selected Answer: C
I opt for option C. since it is a parallel stream we cannot predict the order of the output
upvoted 1 times
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steefaand
1 year, 3 months ago
Selected Answer: D
Answer is D. Tested.
upvoted 1 times
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Ohayou
3 years, 2 months ago
Answer D
upvoted 1 times
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Eason_from_the_future
3 years, 8 months ago
D, tested public static void main(String[] args) { List<String> nums = Arrays.asList("EE", "SE"); String ans = nums.parallelStream().reduce("Java", (a, b) -> a.concat(b)); System.out.println(ans); }
upvoted 1 times
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Svetleto13
4 years ago
D,tested
upvoted 2 times
Svetleto13
3 years, 12 months ago
If we test the code with stream(),not parallelStream(),answer is B.
upvoted 2 times
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JME_CHG
4 years, 2 months ago
B and D are both possibilities... "Java" is not a true identity so can give unexpected results, but due to encounter order, will always be EE before SE...
upvoted 2 times
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laura_lu93
4 years, 2 months ago
tested is D
upvoted 3 times
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Abdullah_Rahahleah
4 years, 4 months ago
Because it's parallelStream,
upvoted 1 times
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