Exam 1z0-808 topic 1 question 82 discussion

aeii is correct

A is correct.Because for obj2 is obj1.So,if we assign i to obj2 .var it will change obj1 also.

public class Vowel { private char var; public static void main (String[] args){ char var1= 'a'; char var2 = var1; var2 = 'e'; Vowel obj1 = new Vowel(); Vowel obj2 = obj1; obj1.var = 'o'; obj2.var = 'i'; System.out.println(var1 +", " +var2); System.out.print(obj1.var +", " + obj2.var); } } a, e i, i

Answer is A and correct, because the obj2 is a same object of obj1 (Vowel obj2 = Vowel obj1), then when change obj2.var to 'i' changes too obj1.var to 'i'. Then print "a, e, i, i".