Exam 1z0-808 topic 1 question 38 discussion

D is not right because it's double checked again after if (qty >=90) {discount = 0.5), reset the discount to 0.

Ok I got why D is wrong. it is wrong in the case if qty is 85 for example. it will go in the first if condition which will make discount = 0.2 all good. Then it will also go in the second if condition where it will go into the else statement and assign discount = 0, making the code not correct

Only A and C are correct

why D is not correct ?

thisis correct

Answer is AC. It boring to test... It is necessary to change the value of the variable 'qty' to perform the test. The code can be compiled on the command line and the value passed by "args" or simply change the value of this variable directly in the code. That's it. To test: public static void main(String[] args) { double discount = 0; int qty = Integer.parseInt(args[0]); qty=90; // change here // Answer A if (qty >= 90) { discount = 0.5; } System.out.println(discount); if (qty > 80 && qty < 90) { discount = 0.2; } System.out.println(discount); // Answer C discount = (qty >= 90) ? 0.5 : (qty > 80)? 0.2: 0; System.out.println(discount); }

A and C are the correct options because in Option B we are using the discount variable twice, and thus only the second discount's value will be the final updated value in Option D only the case where qty >= 90 will work in Option E everytime the output printed will be 0.2 no matter if the condition is 1st or 2nd.