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С
public class SumTest {
public static void doSum(Integer x, Integer y) {
System.out.println("Integer sum is " + (x + y));
}
public static void doSum(double x, double y) {
System.out.println("Double sum is " + (x + y));
}
public static void doSum(float x, float y) {
System.out.println("Float sum is " + (x + y));
}
public static void main(String[] args) {
doSum(10, 20); // Integer sum is 30
doSum(10.0, 20.0); // Double sum is 30.0
doSum(10.0f, 20.0f); // Float sum is 30.0
}
}
The correct answer is the letter A, there is an overload of the methods. Here's the code:
public class Test {
public static void doSum(Integer x, Integer y) {
System.out.println("Integer sum is " + (x + y));
}
public static void doSum(double x, double y) {
System.out.println("double sum is " + (x + y));
}
public static void doSum(float x, float y) {
System.out.println("float sum is " + (x + y));
}
public static void main (String[] args) {
doSum(10, 20);
doSum(10.0, 20.0);
}
}
Answer is actually C
Integer sum is 30
double sum is 30.0
upvoted 1 times
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C (25%)
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5 months ago