Exam 1z0-809 topic 1 question 60 discussion

Actual exam question from Oracle's 1z0-809

Question #: 60
Topic #: 1

Given the code fragment:
List<String> nL = Arrays.asList("Jim", "John", "Jeff");
Function<String, String> funVal = s -> "Hello : ".contact(s); nL.Stream()
.map(funVal)
.peek(System.out::print);
What is the result?

A. Hello : Jim Hello : John Hello : Jeff
B. Jim John Jeff
C. The program prints nothing.
D. A compilation error occurs.

Show Suggested Answer

Suggested Answer: C 🗳️

by thetech at Dec. 5, 2019, 9:42 a.m.

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speed045

Highly Voted 4 years, 1 month ago

Correct answer is C, since peek is an intermediate lazy operation which will not be evaluated unless the pipeline is ended with a terminating operation.

upvoted 6 times

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asdfjhfgjuaDCV

Most Recent 9 months, 3 weeks ago

C is the correct answer:tested

upvoted 1 times

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steefaand

10 months, 3 weeks ago

Selected Answer: C

C is correct, since there is no terminal operation and Stream is never run.

upvoted 1 times

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nikhil_3011

2 years, 11 months ago

Answer is C. if we use any terminal operation after peek like .count()( even though its bad o/p formatting) then the answer would be A.

upvoted 2 times

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Svetleto13

3 years, 7 months ago

Correct answer is C.If we replace peek with forEach answer is A

upvoted 4 times

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ayzo

3 years, 11 months ago

Answer is A tested: class Testing { public static void main (String[] args) throws IOException{ List<String> nL = Arrays.asList("Jim ", "John ", "Jeff"); Function<String, String> funVal = s -> "Hello : ".concat(s); nL.stream() .map(funVal) .forEach(s-> System.out.print (s)); } } output: Hello : Jim Hello : John Hello : Jeff

upvoted 1 times