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Exam 1z0-819 topic 1 question 40 discussion

Actual exam question from Oracle's 1z0-819

Question #: 40
Topic #: 1

[All 1z0-819 Questions]

Given the code fragment:

What is the result?

A. The compilation fails due to an error in line 2.
B. 201
C. de
D. 203
E. The compilation fails due to an error in line 3.
F. The compilation fails due to an error in line 1.

Show Suggested Answer

Suggested Answer: E 🗳️

by Obalt at Feb. 7, 2023, 7:40 p.m.

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ASPushkin

10 months, 1 week ago

Selected Answer: B

if you don't notice the syntax error on line 3, то //is ok according to Implicit narrowing char d = 100 //returns "int" according to Numeric Promotion Rules (char) x + (char)y

upvoted 1 times

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[Removed]

1 year, 1 month ago

Selected Answer: B

Correct answer is B i did run it and it print 201

upvoted 1 times

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[Removed]

1 year, 10 months ago

E is correct. int = won't compile

upvoted 1 times

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Stavok

2 years ago

Selected Answer: E

E is correct Tested

upvoted 1 times

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Jtic

2 years, 4 months ago

Selected Answer: E

char d = 100, e = 'e' ; // line 1 int x = d ; // line 2 int y = (int) e; // line 3 System.out.println ((char) x + (char) y) ;

upvoted 1 times

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RP384

2 years, 4 months ago

Selected Answer: E

"int =" will fail

upvoted 1 times

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Obalt

2 years, 4 months ago

There is a minor error on line 3. Should be int y = (int)e. Then B is correct answer

upvoted 1 times

KiraguJohn

2 years, 2 months ago

That minor error on line 3 is intentional otherwise an examiner would not expect you to know the ASCII code for all characters.

upvoted 2 times

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Obalt

2 years, 4 months ago

Correct answer is B

upvoted 1 times

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