Exam CAPM topic 1 question 45 discussion

Actual exam question from PMI's CAPM

Question #: 45
Topic #: 1

The project manager has the following information about the estimated duration for an activity:
✑ Most likely [tM] `" 15 days
✑ Pessimistic [tP] `" 20 days
✑ Optimistic [tO] `" 10 days
What is the estimated duration of this activity, according to the triangular distribution technique?

A. 10 days
B. 15 days
C. 12.5 days
D. 5 days

Show Suggested Answer

Suggested Answer: B 🗳️

by nickname12 at Sept. 8, 2020, 1:47 a.m.

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sweety433

9 months, 2 weeks ago

TM+T0+TP/3 - 45/3 = 15 days

upvoted 1 times

sweety433

9 months, 2 weeks ago

TM+T0+TP/3 = 45/3 = 15 days

upvoted 1 times

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EmRH

2 years ago

Why is the answer 15, not 12.5? I thought the triangulation technique is to add all three together, then divide by three.

upvoted 2 times

[Removed]

2 years ago

If you add all three together and divide by three, the answer is 15. (10 + 15 + 20 = 45, 45/3 = 15).

upvoted 5 times

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ChymKuBoy

2 years, 1 month ago

Selected Answer: B

B for sure

upvoted 1 times

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UlrichIng

4 years, 8 months ago

Page 201 of 6th Edition of PMBOK Depending on the assumed distribution of values within the range of the three estimates, the expected duration, tE, can be calculated. One commonly used formula is triangular distribution: tE = (tO + tM + tP) / 3. So the answer is B. 15 Days

upvoted 4 times

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MoonManBlue

4 years, 9 months ago

Correct, should be 15

upvoted 3 times

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nickname12

4 years, 10 months ago

This should be 12.5 E = (O + P + ML)/3

upvoted 2 times

nickname12

4 years, 10 months ago

Sorry 15, not 12.5

upvoted 3 times

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