Exam PCEP-30-02 topic 1 question 3 discussion

x = [0,1,2] x.insert(0,1) #which means insertion in list at zero index.Hence, x = [1,0,1,2] del x[1] # At index 1 in list the element is 0 .Hence x become [1,1,2] print(sum(x) # sum all elements in list [1,1,2] is 4 Hence, Option B is the correct one.

list.insert(index, value)

let's break down the code step by step to understand the result: Code: x = [0, 1, 2] # Step 1: x is initialized as [0, 1, 2]. x.insert(0, 1) # Step 2: Inserts 1 at index 0. x becomes [1, 0, 1, 2]. del x[1] # Step 3: Deletes the element at index 1. x becomes [1, 1, 2]. print(sum(x)) # Step 4: Calculates the sum of elements in x, which is 1 + 1 + 2 = 4. Result: The output of the code is 4.

x=[0,1,2] x=[1,0,1,2] x=[1,1,2] sum=1+1+2=4

The given code performs the following operations: 1. `x = [0, 1, 2]`: Initializes the list `x` with the elements `[0, 1, 2]`. 2. `x.insert(0, 1)`: Inserts the value `1` at index `0`, so the list becomes `[1, 0, 1, 2]`. 3. `del x[1]`: Deletes the element at index `1`, so the list becomes `[1, 1, 2]`. 4. `print(sum(x))`: Calculates the sum of the elements in the list `x` and prints it. Now, the list `x` is `[1, 1, 2]`, and the sum of these elements is `1 + 1 + 2 = 4`. **Expected output:** `4`

x.insert(0,1) >> insert value 1 to x[0] >> The new x = [1,0,1,2] del x[1] >> delete x[1] >> delete value 0 in x sum(x) = 1+1+2 = 4

b is the correct answer