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Exam PCAP-31-03 All Questions

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Exam PCAP-31-03 topic 1 question 18 discussion

Actual exam question from Python Institute's PCAP-31-03
Question #: 18
Topic #: 1
[All PCAP-31-03 Questions]

Assuming that the snippet below has been executed successfully, which of the following expressions will evaluate to True? (Choose two.) string = 'python'[::2] string = string[-1] + string[-2]

  • A. len(string) == 3
  • B. string[0] == 'o'
  • C. string[0] == string[-1]
  • D. string is None
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Suggested Answer: AB 🗳️
by kstr at June 5, 2024, 8:53 p.m.

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Horsefeathers
3 months, 1 week ago
Selected Answer: B
Only B is correct: string = 'python'[::2] string = string[-1] + string[-2] print(len(string) == 3) print(string[0] == 'o') print(string[0] == string[-1]) print(string is None) False True False False
upvoted 1 times
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jarun2024
8 months, 1 week ago
Ans : A & B
upvoted 1 times
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Dave304409
10 months, 1 week ago
A, B is correct string = 'python'[::2] print(string) pto R: print(len(string) == 3 ) string = string[-1] + string[-2] print(string) ot print(string[0] == 'o' )
upvoted 2 times
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DKAT2023
10 months, 2 weeks ago
B is the correct
upvoted 1 times
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kstr
11 months, 1 week ago
Sorry only B: string = 'python'[::2] string = string[-1] + string[-2] print(len(string) == 3 ) print(string[0] == 'o' ) print( string[0] == string[-1] ) print( string is None)
upvoted 2 times
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kstr
11 months, 1 week ago
Only C is True string = 'python'[::2] string = string[-1] + string[-2] print(len(string) == 3 ) print(string[0] == 'o' ) print( string[0] == string[-1] ) print( string is None)
upvoted 1 times
...
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