Exam PCEP-30-02 topic 1 question 7 discussion

To determine the output of this code, let's go through it step by step: dct = {} creates an empty dictionary. dct['1'] = (1, 2) adds a key-value pair to the dictionary. The key is the string '1', and the value is the tuple (1, 2). dct['2'] = (2, 1) adds another key-value pair. The key is the string '2', and the value is the tuple (2, 1). The for loop iterates over the keys of the dictionary using dct.keys(). For each key x, it prints dct[x][1] with end=''. This means it's printing the second element of each tuple (index 1), and the end='' argument prevents a newline after each print. So, when we iterate over the keys: For key '1', it will print 2 (the second element of (1, 2)) For key '2', it will print 1 (the second element of (2, 1)) These will be printed on the same line because of end=''. Therefore, the output will be: 21

I see what the program is doing. The other explanation is kind of confusing. So the program is doing the following: It creates an empty dictionary. So its format is "x":"other value here". So, the code creates a key and a value: dct["1"]=(1,2) = dct={ "1":"1,2"} dct["2"]=(2,1) = dct={"2":"2,1"} Thus, dct = {"1": "1,2" , "2" : "1,2"} for each key in dct: print( the first element of each key in dct) so key "1" = 2(first element) and key 2 = 1(first element) which gives us 21 here.

dct = {} dct['1'] = (1,2) #second element of this key is 2 dct['2'] = (2,1) #second element of this key is 1 for x in dct.keys(): print(dct[x][1], end='') #print out the second element of each key continuously #>>> the answer is 21 (D)

d is the correct answer

answer : 21 2 is of the dct['1'] and 1 is of dct['2']