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Exam PCAP-31-03 topic 1 question 70 discussion

Actual exam question from Python Institute's PCAP-31-03
Question #: 70
Topic #: 1
[All PCAP-31-03 Questions]

What is the expected behavior of the following code?

my_list = [i for i in range(5)]
m = [my_list[i] for i in range(5) if my_list[i] % 2 != 0]
print(m)

  • A. the code is erroneus and it will not execute
  • B. it outputs [0, 2, 4]
  • C. it outputs [0, 1, 2, 3, 4]
  • D. it outputs [1, 3]
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Suggested Answer: D 🗳️

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Abbribas
1 month, 2 weeks ago
Selected Answer: D
my_list = [i for i in range(5)] → Creates: [0, 1, 2, 3, 4] m = [my_list[i] for i in range(5) if my_list[i] % 2 != 0] → Filters out odd elements only: my_list[0] = 0 → even → skipped my_list[1] = 1 → odd → included my_list[2] = 2 → even → skipped my_list[3] = 3 → odd → included my_list[4] = 4 → even → skipped → Result: [1, 3]
upvoted 1 times
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zwakenberg
6 months, 1 week ago
Selected Answer: D
List Comprehension: my_list = [i for i in range(5)] This creates a list of integers from 0 to 4: [0, 1, 2, 3, 4]. Filtered List Comprehension: m = [my_list[i] for i in range(5) if my_list[i] % 2 != 0] This iterates over the indices 0 to 4 and includes my_list[i] in the new list m only if my_list[i] % 2 != 0 (i.e., the element is odd). The odd elements in my_list are 1 and 3. Output: print(m) prints the list m, which contains the odd elements [1, 3]
upvoted 2 times
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