Length will be 3, the answer is D

The answer B is OK because the name of the variable "1st" is incorrect. Variables names can contain numbers but not at the begin.

>>> lst = [x for x in range(5)] >>> lst [0, 1, 2, 3, 4] >>> lst = list(filter(lambda x: x % 2 == 0, lst)) >>> lst [0, 2, 4] >>> print(len(lst)) 3

print(lst) [0, 2, 4] The answer: D

>>> print(lst) [0, 2, 4] >>>

If you ignore the fact the 1st is an invalid variable name and the spacing is all wonky, then the answer is D. It might be lst but its hard to know or sure because formating on this site is a nightmare for programming questions. Anyway, if we ignore that, then we evaluate each item in the list [0,1,2,3,4] according to the lamba function x % 2 == 0, where x is each subsequent item in that list. If they evaluate to true, then that item is allowed to pass the filter into the new list (that is created by the list() function). Remember that modulo % returns the remainder of the division (regardless of which way you go) 0 % 2 returns 0 1 % 2 returns 1 2 % 2 returns 0 3 % 2 returns 1 4 % 2 returns 0 only the items that evaluated to 0 will pass the filter. Thats [0,2,4] with a length of 3

It is a format issue by examtopics, read 1 as l (letter) everywhere in code.. so, D is the correct answer for this!

B is the correct answer because there is no list named "list".

B. you can not have a variable name where the initial character is a number '1st' it could be 'st1'. The equal sign has a gap which is not recognised in python = =, it should have been ==

the answer is D

Correct Answer is D. If there is space, then it wouldn't give runtime error, it will give compile time error.

It is not B because either error is synthax or compiler. It is never runtime error

The answer is #B. The code will cause a runtime exception. The actual error is: #TypeError: object of type 'filter' has no len() we cant get the len of a filter object so we can not print(len(list) The only answer is B and noting else.

It is D. len(lst) = 3

assuming code is correct: D. 3

When you try to run this code, it errors, correct answer is B

1st is not valid variable name. It will give runtime error