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Exam PCAP topic 1 question 108 discussion

Actual exam question from Python Institute's PCAP
Question #: 108
Topic #: 1
[All PCAP Questions]

What is the expected behavior of the following code?

  • A. it outputs [1, 3]
  • B. the code is erroneous and it will not execute
  • C. it outputs [3, 1]
  • D. it outputs [4, 2, 0]
Show Suggested Answer Hide Answer
Suggested Answer: C 🗳️
by kungtabumi at Oct. 16, 2021, 6:31 a.m.

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seaverick
1 year, 3 months ago
Selected Answer: B
my_list = [i for i in range(5)] m = [my_list[i] for i in range(4,0,-1)] if my_list[i] %2 != 0] print(m) output -> SyntaxError: unmatched ']' Ans -> B
upvoted 2 times
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kstr
1 year, 5 months ago
The answer is right B tested
upvoted 1 times
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Janpcap123
1 year, 8 months ago
Based on the exact code presented the correct answer is B, if you remove the ']' from the code obviously the answer becomes [3,1] BUT the fact is ']' exists in the code so you must select B as the correct answer and nor speculate on 'what if's'
upvoted 1 times
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andr3
2 years, 1 month ago
Selected Answer: C
In [89]: mylist = [ i for i in range(5)] In [90]: mylist Out[90]: [0, 1, 2, 3, 4] In [91]: m = [mylist[i] for i in range (4,0,-1) if mylist[i] % 2!=0 ] In [92]: m Out[92]: [3, 1]
upvoted 4 times
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Nenggg
2 years, 4 months ago
If there is no "]" after the for loop then, C would be the answer. Otherwise, "]" cause the error and answer will be B
upvoted 2 times
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rotimislaw
2 years, 5 months ago
Selected Answer: B
B: There's an ']' before 'if' statement so the code is erroneous If that wasn't the case, the [3, 1] would be printed
upvoted 3 times
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pablohm83
2 years, 7 months ago
Selected Answer: C
C. I suppose there is a typo error in the transcription
upvoted 1 times
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macxsz
3 years ago
Selected Answer: B
B. the code is erroneous and it will not execute
upvoted 2 times
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rocky48
3 years ago
Selected Answer: C
>>> my_list = [i for i in range(5)] >>> m = [my_list[i] for i in range(4,0,-1) if my_list[i] % 2 != 0] >>> print(m) [3, 1]
upvoted 3 times
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sadako11
3 years, 2 months ago
Syntax Error. There is an unmatched extra bracket. (maybe at typo who knows?) Without it the answer is [3,1]
upvoted 4 times
rocky48
3 years ago
>>> my_list = [i for i in range(5)] >>> m = [my_list[i] for i in range(4,0,-1) if my_list[i] % 2 != 0] >>> print(m) [3, 1]
upvoted 2 times
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DTL001
3 years, 4 months ago
Answer is C my_list = [i for i in range(5)] m = [my_list[i] for i in range(4,0,-1) if my_list[i] % 2 != 0 ] print(m) [3,1]
upvoted 1 times
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DTL001
3 years, 4 months ago
it outputs [3, 1]
upvoted 1 times
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kungtabumi
3 years, 6 months ago
right answer is C
upvoted 2 times
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