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Exam 5V0-21.19 All Questions

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Exam 5V0-21.19 topic 1 question 74 discussion

Actual exam question from VMware's 5V0-21.19
Question #: 74
Topic #: 1
[All 5V0-21.19 Questions]

What is the formula for determining the minimum number of vSAN hosts in a cluster necessary to support a Failures To Tolerate (FTT) policy, where FTT=n?

  • A. n+1
  • B. n+2
  • C. 2n+1
  • D. 2n+2
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Suggested Answer: C 🗳️
To tolerate n failures, you need 2n + 1 ESXi host in the vSAN cluster.
Reference:
https://searchvmware.techtarget.com/answer/How-can-a-VM-storage-policy-improve-vSAN-cluster-redundancy

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avilis
Highly Voted 4 years, 12 months ago
C is correct. "Minimum host requirements for mirroring as a failure tolerance method used an algorithm of 2n+1 where an is the number of Failures to Tolerate." https://storagehub.vmware.com/t/vsan-space-efficiency-technologies/host-requirements-1/
upvoted 6 times
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Lazylinux
Most Recent 3 years, 6 months ago
Selected Answer: C
C easy give away
upvoted 1 times
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safodz
4 years ago
it is an ambiguous question in the case of RADI5/6 the formula is 2n+2
upvoted 1 times
shav007
4 years ago
it says minimum so the it should be 2n+1
upvoted 1 times
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AllenHuang
4 years, 2 months ago
C is correct
upvoted 1 times
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diegof1
4 years, 5 months ago
C is correct. • For n failures that are tolerated, n+1 copies of the object are created. • For n failures that are tolerated, 2n+1 hosts contributing storage are required. • Default value: 1. Taken from vSAN 6.7 Deploy and Manage Lecture Manual - Level of Failures to Tolerate section
upvoted 2 times
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Aolivera
4 years, 10 months ago
Copies of data = 2n+1. Number of hosts needed is = n+1
upvoted 2 times
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jasonv
4 years, 11 months ago
2n+1 is gold rule
upvoted 1 times
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alfred
5 years ago
since this is minimum... the answer should be n+1.
upvoted 1 times
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