Exam SY0-501 topic 1 question 304 discussion

To elect the root bridge in the LAN, first check the priority value. The switch having the lowest priority will win the election process. If Priority Value is the same then it checks the MAC Address; the switch having the lowest MAC Address will become the root bridge.

B is the correct answer: THE ROOT BRIDGE ELECTION PROCESS If there is a tie between two switches having the same priority value, then the switch with the lowest MAC address becomes the Root Bridge." http://www.firewall.cx/networking-topics/protocols/spanning-tree-protocol/1054-spanning-tree-protocol-root-bridge-election.html

Answer:B When comparing two bridge IDs, the priority portions are compared first and the MAC addresses are compared only if the priorities are equal. The switch with the lowest priority of all the switches will be the root; if there is a tie, then the switch with the lowest priority and lowest MAC address will be the root. For example, if switches A (MAC = 0200.0000.1111) and B (MAC = 0200.0000.2222) both have a priority of 32768 then switch A will be selected as the root bridge

Answer is 'B'. Lowest MAC address will become default root bridge unless other metrics are used to specify otherwise. (Don't just rely on other dumps for answers people, put in the work and study BOOKS.)

Its B. Root bridge selection is based on Lowest MAC and priority. Ppl commenting all other sites have answer "C", lol xD

I agree that the answer is B. this is more of a Network+ question. In Net+ material i remember that the lowest MAC address defaults to root unless otherwise elected.

I think it is B. The switch has the lowest MAC address

Three other sites agree with: C. The switch has spanning tree loop protection enabled

Correct answer is C.

Is this the right answer ? Can anyone explain me

The question should read "slow performing edge switch" and not "law performing edge switch".